CODEWITHSUNDEEP
c++reference
Samuel
Samuel

Reputation: 73

Returning reference from a function and modifying it

#include<iostream>
int& f(){
 static int x = 0;
 x++;
 return x;
}

int main(){

  f() += 1; //A

 f() = f() + 1; //B
 std::cout << f();
}

The above code outputs 6 on gcc and 5 on MSVC. Now when I modify A and B to f()=f() I get 5 on both compilers. What is the big deal here? Is the behavior undefined. If yes , why?

Upvotes: 3

Views: 93

Answers (1)

anon
anon

Reputation:

It is undefined, because in this code:

f() = f() + 1;

it is not defined which call to f() happens first.

Upvotes: 5

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