CODEWITHSUNDEEP
scala
jdprasad
jdprasad

Reputation: 367

Divide string into two parts based on separator in Scala

input:

myString = ""FILTER=(ID=123,Description=456)""

output:

FILTER, (ID=123,Description=456)

basically divide the string into two parts How can i achieve this ?

Want something equivalent to str.partition(sep) as in python

Upvotes: 0

Views: 1214

Answers (2)

Christian Hirsch
Christian Hirsch

Reputation: 2056

The span-method could also be helpful for you

   val myString = "FILTER=(ID=123,Description=456)"
   //myString: String = FILTER=(ID=123,Description=456)

   myString.span(_!='=')
   //res9: (String, String) = (FILTER,=(ID=123,Description=456))

Upvotes: 0

The Archetypal Paul
The Archetypal Paul

Reputation: 41769

You want split with a limit parameter (but you don't get the separator as an element as in the Python partition)

val myString = "FILTER=(ID=123,Description=456)"     
myString.split("=", 2)  
//> res0: Array[String] = Array(FILTER, (ID=123,Description=456))

It's actually a java method - see here

Upvotes: 4

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