Bokeh package in Python: How to use rgb to color option

Question

Lets say I have the following code:

from bokeh.plotting import *
p= figure(title = 'title',x_axis_label='x',y_axis_label='y')
p.circle(-25,25, radius=5, color="black", alpha=0.8)
show(p)

I am trying to find in documentation how to store color with rgb values but cant find it. What I mean something like the following:

p.circle(-25,25, radius=5, color=[0,0,0], alpha=0.8)

Is there a way to implement it?

Answer 1

bokeh supports color entry using multiple methods:

• Named colors (like green or blue)
• RGB hex values like #FF3311
• 3-tuple signifying RGB values like (0, 0, 0)
• 4-tuple signifying RGB-Alpha values like (0, 0, 0, 0.0)

So for you, you could call your function like this:

p.circle(-25, 25, radius=5, color=(0, 0, 0), alpha=0.8)

This behavior is defined in the Styling - Specifying Colors section of bokeh documentation.

---

I have sample code here which demonstrates this:

#!/usr/bin/env python
from bokeh.plotting import figure, output_file, show

# output to static HTML file
output_file("circle.html", title="circles")

# create a new plot with a title and axis labels, and axis ranges
p = figure(title="circles!", x_axis_label='x', y_axis_label='y',
           y_range=[-50, 50], x_range=[-50, 50])

# add a circle renderer with color options
p.circle(-25, 25, radius=5, color=(0,0,0), alpha=0.8)
p.circle(-10, 5, radius=5, color=(120, 240, 255))

# show the results
show(p)

It generates a plot that looks like this:

Your code above, when I run this:

from bokeh.plotting import figure, output_file, show

output_file("circle.html")
p= figure(title = 'title',x_axis_label='x',y_axis_label='y')
p.circle(-25,25, radius=5, color="black", alpha=0.8)
show(p)

Generates this: