CODEWITHSUNDEEP
pythonpython-3.4
S Aylward
S Aylward

Reputation: 47

Invalid token when using 001 in Python 3.4.3

I've looked for a solution to this online but haven't found anything relevant. An assignment for my course requires me to make a program where the computer will try to guess a number the user has input. The number needs to be between 001 and 100, so I have started by trying to ensure the user can only input numbers within that range.

The code i have so far: 

import random
code=(int(input("Input a three digit code. Must be more than 001 and less than 100.")))
print(code)
if (code < 001) or (code > 100): 
    print ("Invalid code")
elif (code > 001) or (code < 100):
    print ("Valid code")

It works fine with 001 changed to 1, but if i run it with 001 i get an Invalid Token error. This needs to be done in Python 3.4.3. Any sort of help would be greatly appreciated.

Upvotes: 3

Views: 694

Answers (1)

Tim Pietzcker
Tim Pietzcker

Reputation: 336458

Integers can't have leading zeroes in Python. Leading zeroes were previously (Python 2) used to denote octal numerals. Since many people didn't know that and were confused why 070 == 56, Python 3 made leading zeroes illegal.

You shouldn't be converting code to an integer - only store actual numbers (that you intend to do calculations with) in numerical variables. Keep the string:

while True:
    code = input("Input a three digit code. Must be more than 001 and less than 100.")
    try:
        value = int(code)
    except ValueError:
        print("Invalid code")
        continue
    if 1 <= value <= 100: 
        print ("Valid code")
        break
    else:
        print ("Invalid code")

Upvotes: 3

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