Reputation: 302
so I'm having this problem where I can't unwrap an optional for outputting it into the label, I've even tried just printing it in the console and it still gives me an optional
The code and array are in different files.
Code It's in a VC:
for var i = 0; i < stateName.count; i++ {
if tax.state == stateName[i][0] {
stateName[i][1] = Double(taxNumb.text!)!
print(stateName[i][1])
output.text = String(stateName[i][1])
}
}
Array Code I made this in an empty swift file:
var tax : Taxes? = nil
var stateName = [
["AK - Alaska", tax?.alaska!],
["AL - Alabama", tax?.alabama!],
["AR - Arkansas", tax?.arkansas!],
["AZ - Arizona", tax?.arizona!],
["CA - California", tax?.california!]
]
Upvotes: 0
Views: 145
Reputation: 57174
As I wrote in my comment to your previous question use the "Nil Coalescing" ??
operator:
output.text = String(stateName[i][1] ?? "not set")
Or using the alternate swift String magic
output.text = "\(stateName[i][1] ?? "not set")"
The operator returns the first value if it not nil, otherwise it returns the second value.
Upvotes: 1