Reputation: 133
I've been thinking for a while about this problem:
What's the number of ways of correctly* arranging 2*n parenthesis.
*A correctly arranged sequence of parenthesis has an equal number of open and closed parenthesis at its end and a larger or equal amount of open parenthesis than the closed ones throughout the sequence.
For example, for n=3
, there are 5
ways: ((())), ()(()), ()()(), (())(), (()())
.
I've been thinking of representing nested parenthesis as trees, but didn't get far.
Upvotes: 10
Views: 4032
Reputation: 222761
Your example equivalent to the number of Dyck words, which can be counted with combinatorics and will be equal to Catalan number:
Upvotes: 14