Reputation: 43
rocksteady's solution worked
He did originally refer to dictionaries. But the following code to send the JSON string also worked wonders using requests:
import requests
headers = {
'Authorization': app_token
}
url = api_url + "/b2api/v1/b2_get_upload_url"
content = json.dumps({'bucketId': bucket_id})
r = requests.post(url, data = content, headers = headers)
I'm working with an API that requires me to send JSON as a POST request to get results. Problem is that Python 3 won't allow me to do this.
The following Python 2 code works fine, in fact it's the official sample:
request = urllib2.Request(
api_url +'/b2api/v1/b2_get_upload_url',
json.dumps({ 'bucketId' : bucket_id }),
headers = { 'Authorization': account_authorization_token }
)
response = urllib2.urlopen(request)
However, using this code in Python 3 only makes it complain about data being invalid:
import json
from urllib.request import Request, urlopen
from urllib.parse import urlencode
# -! Irrelevant code has been cut out !-
headers = {
'Authorization': app_token
}
url = api_url + "/b2api/v1/b2_get_upload_url"
# Tested both with encode and without
content = json.dumps({'bucketId': bucket_id}).encode('utf-8')
request = Request(
url=url,
data=content,
headers=headers
)
response = urlopen(req)
I've tried doing urlencode()
, like you're supposed to. But this returns a 400 status code from the web server, because it's expecting pure JSON. Even if the pure JSON data is invalid, I need to somehow force Python into sending it.
EDIT: As requested, here are the errors I get. Since this is a flask application, here's a screenshot of the debugger:
Adding .encode('utf-8')
gives me an "Expected string or buffer" error
EDIT 2: Screenshot of the debugger with .encode('utf-8')
added
Upvotes: 4
Views: 24643
Reputation: 2560
Since I have a similar application running, but the client still was missing, I tried it myself. The server which is running is from the following exercise:
Miguel Grinberg - designing a restful API using Flask
That's why it uses authentication.
But the interesting part: Using requests
you can leave the dictionary as it is.
Look at this:
username = 'miguel'
password = 'python'
import requests
content = {"title":"Read a book"}
request = requests.get("http://127.0.0.1:5000/api/v1.0/projects", auth=(username, password), params=content)
print request.text
It seems to work :)
Update 1:
POST requests are done using requests.post(...) This here describes it well : python requests
Update 2:
In order to complete the answer:
requests.post("http://127.0.0.1:5000/api/v1.0/projects", json=content)
sends the json-string.
json
is a valid parameter of the request and internally uses json.dumps()
...
Upvotes: 3