CODEWITHSUNDEEP
c
Michi
Michi

Reputation: 5297

Get time difference using current time

I made a Math game for my Kid (8 years old) and at some point i decided to show him how much time did he needed to answer to that question, so i decided to use the function time here.

I wrote the following program:

#include <time.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>

struct setClock{
    int hour;
    int minutes;
    int seconds;
};

struct setClock currTime(void);
void timeCheck(struct setClock myClock[2]);

int main(void){
    struct setClock myClock[2];

    myClock[0] = currTime();
    printf("Start Time: %d:%d:%d\n\n", myClock[0].hour, myClock[0].minutes, myClock[0].seconds );

    sleep(5);

    myClock[1] = currTime();
    printf("End Time:   %d:%d:%d\n", myClock[1].hour, myClock[1].minutes, myClock[1].seconds );

    timeCheck(myClock);

    return 0;

}

struct setClock currTime(void){
    struct setClock ret;
    struct tm *tm;
    time_t myTime;

    myTime=time(NULL);
    tm=localtime(&myTime);

    ret.hour = tm->tm_hour;
    ret.minutes = tm->tm_min;
    ret.seconds = tm->tm_sec;

    return ret;
}

void timeCheck(struct setClock myClock[2]){
    int hour;
    int minute;

    time_t end, start;
    double diff;

    start = (time_t)((myClock[0].hour * 60 + myClock[1].hour) * 60) ;
    end   = (time_t)((myClock[0].minutes * 60 + myClock[1].minutes) * 60) ;

    if( end < start ){
        end += 24 * 60 * 60 ;
    }

    diff = difftime(end, start);

    hour = (int) diff / 3600;
    minute = (int) diff % 3600 / 60;
    printf("\n\n");
    printf("The elapsed time is  %d Hours - %d Minutes\n", hour, minute);
}

When i run it, i get different outputs like:

Start Time: 16:19:2

End Time:   16:19:7


The elapsed time is  3 Hours - 3 Minutes

Or:

Start Time: 16:19:14

End Time:   16:19:19


The elapsed time is  1 Hours - 1 Minutes

But the output should be:

The elapsed time is  0 Hours - 0 Minutes

I really don't know what's wrong with my timeCheck function. Any way if i fix it some how i need to expand it to print:

The elapsed time is  0 Hours - 0 Minutes - 5 Seconds.

Upvotes: 0

Views: 233

Answers (1)

MikeCAT
MikeCAT

Reputation: 75062

start = (time_t)((myClock[0].hour * 60 + myClock[1].hour) * 60) ;
end   = (time_t)((myClock[0].minutes * 60 + myClock[1].minutes) * 60) ;

This code seems nonsense. I think this should be

start = (time_t)((myClock[0].hour * 60 + myClock[0].minutes) * 60 + myClock[0].seconds) ;
end   = (time_t)((myClock[1].hour * 60 + myClock[1].minutes) * 60 + myClock[1].seconds) ;

Then, have the function print what you want.

  1. add a variable int second; after int minute;
  2. add calculation second = (int) diff % 60; after minute = (int) diff % 3600 / 60;
  3. have it print the result
    printf("The elapsed time is %d Hours - %d Minutes - %d Seconds.\n", hour, minute, second);

Upvotes: 2

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