Reputation: 399
In Microsoft SQL Server 2012 or above, is it possible to convert a datetime value to Unix time stamp in a single select statement? If so, how can it be done?
Upvotes: 26
Views: 92877
Reputation: 592
my function with localization
CREATE FUNCTION UNIX_TIMESTAMP(@ctimestamp datetime)
RETURNS integer
AS
begin
return DATEDIFF(second,'1970-01-01',GETUTCDATE())+datediff(second,GETDATE(),@ctimestamp)
end
then i use value in js code
new Date(unixSec*1000)
Upvotes: 0
Reputation: 41
maybe this answer will help someone... If you have a problem when you try to convert datetime using datediff function to number of seconds (mssql message: The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart.) then use:
select cast(datediff(d,'1970-01-01',@d1) as bigint)*86400+datediff(s,dateadd(day, datediff(day, 0, @d1), 0),@d1)
if you have ms sql server 2016+ use DATEDIFF_BIG function
Upvotes: 4
Reputation: 958
As Peter Halasz mentions in T-SQL DateTime to Unix Timestamp:
Converting a datetime to unix timestamp is easy, but involves error prone typing the following:
@timestamp=DATEDIFF(second,{d '1970-01-01'},@datetime)
Where @datetime is the datetime value you want to convert. The {d ‘yyyy-mm-dd’} notation is an ODBC escape sequence.
The function:
CREATE FUNCTION UNIX_TIMESTAMP ( @ctimestamp datetime ) RETURNS integer AS BEGIN /* Function body */ declare @return integer SELECT @return = DATEDIFF(SECOND,{d '1970-01-01'}, @ctimestamp) return @return END
Try it out now like below @O A:
SELECT UNIX_TIMESTAMP(GETDATE());
Upvotes: 53