CODEWITHSUNDEEP
python
troozers
troozers

Reputation: 213

Checking a value falls between three ranges in Python

I am currently learning Python and want to ensure I am using good python practices and need some help in finding the best way of checking whether a value falls between different ranges.

Basically I am trying to find whether a cpu utilization is between 0-33 (green), 34-66 (amber) or 67-100 (red). Here's my current code;

green = 33
amber = 66
red   = 100  # Probably not needed, but there for completeness

if cpu <= green:
   print "green"
elif cpu > amber:
   print "red"
else:
   print "amber"

Is there a better way to achieve this in Python?

I've looked at "Interval Comparisons" and that doesn't seem to quite fit the bill - although it is entirely possible that I haven't understood them correctly.

Any help is greatly appreciated.

Upvotes: 3

Views: 157

Answers (3)

Daniel Roseman
Daniel Roseman

Reputation: 599628

It's hardly any simpler in your case, but in general you can the bisect module for comparisons like this.

limits = [33, 66, 100]
names = ['green', 'amber', 'red']
interval = bisect.bisect_left(limits, cpu)
print names[interval]

Upvotes: 2

newtover
newtover

Reputation: 32094

It's a trivial piece of code, and is readable enough. But if you had more intervals, you would need a loop. Here is an example:

for level_max, level in [(33, 'green'), (66, 'amber'), (100, 'red')]:
    if cpu <= level_max:
        print level
        break

Upvotes: 0

wim
wim

Reputation: 362826

That is fine. This might be more readable, because the order of logic in the code is matching the escalation of levels:

if cpu <= green:
   print "green"
elif cpu <= amber:
   print "amber"
else:
   print "red"

Upvotes: 2

Related Questions