CODEWITHSUNDEEP
javamysqlspringhibernatespring-mvc
Sreemat
Sreemat

Reputation: 626

Spring MVC -HIbernate-MySQL

I am developing an application with Spring MVC , Hibernate and database MySQL Controller handle the request and response. Hibernate handles the database transaction.

My problem is when one or two access the service it works fine, but for more than that work fine for some time, but after that I get the error frequently lock time out

//My sample Controller code

 @RequestMapping(value = "Bank", method = RequestMethod.GET)
    public ResponseEntity<List<Bank>> getAllBank(@RequestHeader int data) {
        try {
            //My DAO implementation class for bank table
            bankdao = new BankDAOImpl();
            List<Bank> bank = bankdao.getAllBank(data);

            return new ResponseEntity<List<Bank>>(bank, HttpStatus.OK);
        } catch (HibernateException he) {
            return new ResponseEntity<>(HttpStatus.INTERNAL_SERVER_ERROR);
        } catch (Exception e) {
            e.printStackTrace();
            return new ResponseEntity<>(HttpStatus.INTERNAL_SERVER_ERROR);
        }
    }

//My DAO implementation code

public List<Bank> getAllBank(int organizationId) throws HibernateException {
//I'm opening session in every function
Session session = SessionFactoryUtil.getSessionFactory().openSession();
        try {
            session.beginTransaction();
            Criteria criteria = session.createCriteria(Bank.class);
            criteria.add(Restrictions.eq("organizationId", organizationId));
            criteria.add(Restrictions.eq("deleteFlag", false));
            criteria.addOrder(Order.asc("bankName"));
            List<Bank> ls=criteria.list();
            return ls;
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        } finally {
            session.getTransaction().commit();
            session.close();
        }

That session causing the problem If I create a separate session factory for all functions instead of open a session

Will it solve my problem?

Upvotes: 1

Views: 162

Answers (1)

v.ladynev
v.ladynev

Reputation: 19976

You shouldn't create a separate session factory for every method. Just open a session. May be a problem is your incorrect way of working with transactions. You should do it this way

public List<Bank> getAllBank(int organizationId) throws HibernateException {
    //I'm opening session in every function
    Session session = SessionFactoryUtil.getSessionFactory().openSession();
    Transaction tx = null;
            try {
                tx = session.beginTransaction();
                Criteria criteria = session.createCriteria(Bank.class);
                criteria.add(Restrictions.eq("organizationId", organizationId));
                criteria.add(Restrictions.eq("deleteFlag", false));
                criteria.addOrder(Order.asc("bankName"));
                List<Bank> ls=criteria.list();
                tx.commit();// commit here
                return ls;
            } catch (Exception e) {
                e.printStackTrace();
                if (tx != null) {
                  tx.rollback();// rollback here
                } 
                return null;
            } finally {
                session.close();
            }
    }

May be a problem is your SessionFactoryUtil. It would be interesting to see it.

Upvotes: 2

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