Reputation: 39
i have an html source like this;
<ul class="menu">
<li class="submenuitem">
<a title="" href="/mysite/planning">Planning</a>
</li>
<li class="submenuitem">
<a title="" href="/mysite/planning-system">Planning System</a>
</li>
<li class="submenuitem">
<a title="" href="/mysite/planning/partners"> Planning Partners</a>
</li>
</ul>
I want to get all href urls below in every "li" tag using selenium web driver in Java. I tried the following code below;
List<WebElement> links =driver.findElements(By.cssSelector("submenuitem"));
for (int i = 0; i < links.size(); i++)
{
links.getindex(i).getAttribute("href")
}
But links.getAttribute("href") is returning null.
Upvotes: 1
Views: 2898
Reputation: 50819
The problem is in By.cssSelector("submenuitem")
, it should be
By.cssSelector(".submenuitem")
or By.className("submenuitem")
Another way could be
List<WebElement> links = driver.findElements(By.cssSelector("[href*='/mysite']"));
That will give you all the href
which contains "/mysite"
Upvotes: 1