CODEWITHSUNDEEP
cstringreverse
zix
zix

Reputation: 23

Using C move the position of each character in a string to it's right circularly from it's current position

I have to move one character at a time in a string input by the user. At each iteration, the program moves characters to the right from their current place circularly. That is the first character is moved to 2nd place, 2nd character is moved to 3rd place and so on. The last character is moved to 1st place. After characters are moved, the program must also print the new string in each iteration. The iterations are continued till the original string is got back.

For example user enters the string: 'cat'

After first iteration string is: 'tca'

After second iteration string is: 'atc'

and third iteration: 'cat' (which is same as and program finish)

I wrote a code that reverses an entire string. But, I really have no idea how to move one character at a time. The code is as shown below:

#include <stdio.h>
#include <conio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

main ()
{
    char  word[20];
    printf("enter word:");
    int d,i;
    scanf("%s",&word);
    d = strlen(word);

    for(i=d-1; i >= 0; i--)
        printf("%c",word[i]);
}

Upvotes: 2

Views: 17037

Answers (2)

Itban Saeed
Itban Saeed

Reputation: 1666

Possible Solution:

From the sample output it seems like you need to access the string like a circular array. In that case you may need to iterate the string from index (size - move_number) each time and then print the indices by accessing them like a circular array.

Updated Code: 

#include <stdio.h>
#include <conio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

void main()

{
    char  word[20];
    printf("enter word:");
    int d, i;
    scanf("%s", &word);
    d = strlen(word);

    for (i = d - 1; i >= 0; i--) 
    {
        int j = i;
        do
        {
            printf("%c", word[j]);   //Printing each index
            j = (j + 1) % d;        //computing the next index to print
        }
        while (j != i);             //Condition which determines that whole string is traversed
        printf("\n");
    }
}

Hope this helps you in understanding the logic behind the solution.

Upvotes: 2

phoenix
phoenix

Reputation: 3159

declare a var j and replace your for loop with this:

   for (i = d-1; i >=0; i--) {
        j = i;
        printf("%c",word[j]);
        j = (j + 1) % d;
        while ( j != i) {
            printf("%c",word[j]);
            j = (j + 1) % d;
        }
        printf ("\n"):
    }

Upvotes: 2

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