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javaif-statementbitwise-operators
sevenxuguang
sevenxuguang

Reputation: 177

How can I evaluate the bitwise operator in this condition?

I just practice some basic Java practice problems and this below shows up.

if((b2 = false) | (21 % 5)>2) return true;

So b2 is assigned with false and 1 > 2 is certainly false, but how do we evaluate "|" ? should it return true?

Upvotes: 1

Views: 135

Answers (2)

khelwood
khelwood

Reputation: 59096

b2 = false assigns false to the variable b2, and the expression has the value false. | on booleans means "or" (without short-circuit), so it evaluates both operands, and the outcome is true if either operand is true.

It is not a bitwise operator. If you use | on integers, it is a bitwise operator. If you use | on booleans, it is a logical operator.

Edit:

|| is a short-circuit operator. If you write (a() || b()), and a() evaluates to true, then b() will not be evaluated, because the result of the or must be true. Single | does not short-circuit, so both operands are always evaluated.

Upvotes: 2

Florian Schaetz
Florian Schaetz

Reputation: 10652

(b2 = false)

(Edited after khelwood's correction) This is also an assignment, not just a logical operation, so be careful for side effects.

And yes, for a boolean, "|" is "or" (and not bitwise), so if the first operator is true, it will always be true.

Upvotes: 1

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