Reputation: 275
Hi I have the following style of table under MS Access: (I didn't make the table and cant change it)
Date_r | Id_Person |Points |Position
25/05/2015 | 120 | 2000 | 1
25/05/2015 | 230 | 1500 | 2
25/05/2015 | 100 | 500 | 3
21/12/2015 | 120 | 2200 | 1
21/12/2015 | 230 | 2000 | 4
21/12/2015 | 100 | 200 | 20
what I am trying to do is to get a list of players (identified by Id_Person) ordered by the points difference between 2 dates.
So for example if I pick date1=25/05/2015 and date2=21/12/2015 I would get:
Id_Person |Points_Diff
230 | 500
120 | 200
100 |-300
I think I need to make something like
SELECT Id_Person , MAX(Points)-MIN(Points)
FROM Table
WHERE date_r = #25/05/2015# or date_r = #21/12/2015#
GROUP BY Id_Person
ORDER BY MAX(Points)-MIN(Points) DESC
But my problem is that i don't really want to order by (MAX(Points)-MIN(Points)) but rather by (points at date2 - points at date1) which can be different because points can decrease with the time.
Upvotes: 0
Views: 45
Reputation: 1270181
One method is to use first
and last
However, this can sometimes produce strange results, so I think that conditional aggregation is best:
SELECT Id_Person,
(MAX(IIF(date_r = #25/05/2015#, Points, 0)) -
MIN(IIF(date_r = #21/05/2015#, Points, 0))
) as PointsDiff
FROM Table
WHERE date_r IN (#25/05/2015#, #21/12/2015#)
GROUP BY Id_Person
ORDER BY (MAX(IIF(date_r = #25/05/2015#, Points, 0)) -
MIN(IIF(date_r = #21/05/2015#, Points, 0))
) DESC;
Because you have two dates, this is more easily written as:
SELECT Id_Person,
SUM(IIF(date_r = #25/05/2015#, Points, -Points)) as PointsDiff
FROM Table
WHERE date_r IN (#25/05/2015#, #21/12/2015#)
GROUP BY Id_Person
ORDER BY SUM(IIF(date_r = #25/05/2015#, Points, -Points)) DESC;
Upvotes: 1