Reputation: 2072
Suppose there is an array like the below:
a = np.array([[1,2],
[2,3],
[2,3],
[2,3],
[4,5],
[3,4],
[2,3]])
How would I return multiple rows, this is what I would like to achieve (I know the syntax is wrong, but this will give you an idea of what I want to achieve):
a[0:2 & 5:6,:]
I would not be able to pass individual rows because in my actual code I would need to include larger ranges, e.g. 20:60
& 90:160
, etc.
Upvotes: 2
Views: 1783
Reputation: 85432
This works:
>>> a[np.r_[:2, 5:6], :]
array([[1, 2],
[2, 3],
[3, 4]])
The np.r_
:
Translates slice objects to concatenation along the first axis.
Upvotes: 3