CODEWITHSUNDEEP
phpparsing
James
James

Reputation: 43647

PHP get from string

$var = '<img src="http://site.com/some_directory/filename.png"/>';

png can be replaced with any extension.

How to cut everything, except "filename" part?

And write into new variable. In this case:

$name = 'filename';

One more example:

$var = '<img src="http://site.com/directory/subdirectory/Pakahontos.txt"/>';
$name = 'Pakahontos';

Thanks.

Upvotes: 0

Views: 66

Answers (2)

fabrik
fabrik

Reputation: 14365

Here's a basic HTML-parsing tutorial with preg_match. It's parsing images in the example.

Upvotes: 0

Artefacto
Artefacto

Reputation: 97825

preg_match('#([^/]+)\.\w+"#', $var, $matches);
$name = $matches[1];

Note that if $var is actually more complicated (e.g. has arbitrary HTML), you must use other methods (see e.g. DOMDocument).

Upvotes: 3

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