Reputation: 200
I have an array like array('first','12'). So i need to select the table using like condition. which fields have those values.
Example Query:
SELECT * FROM `class` WHERE name LIKE '%first%'
OR father_name LIKE '%first%'
OR age LIKE '%first%'
OR name LIKE '%12%'
OR father_name LIKE '%12%'
OR age LIKE '%12%'
I need to find all the fields with or condition. Is this good or have any other options to find an array of values in all fields.
Thanks,
Upvotes: 0
Views: 87
Reputation: 16963
You can shorten the query using REGEXP
, like this:
SELECT * FROM class
WHERE name REGEXP 'first|12'
OR father_name REGEXP 'first|12'
OR age REGEXP 'first|12';
Here's the reference:
And like you said, if you have an array like this,
$arr = array('first',12);
Then your query should be like this:
$query = "SELECT * FROM class WHERE name REGEXP '" . $arr[0] . "|" . $arr[1] . "' OR father_name REGEXP '" . $arr[0] . "|" . $arr[1] . "' OR age REGEXP '" . $arr[0] . "|" . $arr[1] . "'";
Upvotes: 1