Reputation: 23
I have a data frame as given below:
Name Place a b c sum
xyz mno 1 2 3 6
pqr jkl 4 6 1 11
I would like a command in R script which would help me divide numerical values in column "a", "b" and "c" by value in corresponding "sum" column
hence, my output would be like:
Name Place a b c sum
xyz mno 1/6 2/6 3/6 6
pqr jkl 4/11 6/11 1/11 11
Upvotes: 2
Views: 594
Reputation: 389175
If you want to keep it as a fraction then you can try the fractions
function from the MASS
package
library(MASS)
fractions(unlist(df[, 3:5])/df[,6])
# a1 a2 b1 b2 c1 c2
# 1/6 4/11 1/3 6/11 1/2 1/11
This however, evaluates 2/6
to 1/3
and so on.
Upvotes: 0
Reputation: 887691
We can try
df1[3:5] <- df1[3:5]/df1[6][row(df1[3:5])]
Or just
df1[3:5] <- df1[3:5]/df1[,6]
df1
# Name Place a b c sum
#1 xyz mno 0.1666667 0.3333333 0.50000000 6
#2 pqr jkl 0.3636364 0.5454545 0.09090909 11
Or using dplyr
library(dplyr)
df1 %>%
mutate_each(funs(./df1$sum), a:c)
Or we can use data.table
library(data.table)
setDT(df1)
nm1 <- letters[1:3]
for(j in nm1){
set(df1, i=NULL, j=j, value= df1[[j]]/df1$sum)
}
Upvotes: 2