Reputation: 577
I have been struggling with removing the time zone info from a column in a pandas dataframe. I have checked the following question, but it does not work for me:
Can I export pandas DataFrame to Excel stripping tzinfo?
I used tz_localize to assign a timezone to a datetime object, because I need to convert to another timezone using tz_convert. This adds an UTC offset, in the way "-06:00". I need to get rid of this offset, because it results in an error when I try to export the dataframe to Excel.
Actual output
2015-12-01 00:00:00-06:00
Desired output
2015-12-01 00:00:00
I have tried to get the characters I want using the str() method, but it seems the result of tz_localize is not a string. My solution so far is to export the dataframe to csv, read the file, and to use the str() method to get the characters I want.
Is there an easier solution?
Upvotes: 34
Views: 38916
Reputation: 3283
If you want to remove all timezones from all datetime64 columns you could use this
for col in df.select_dtypes(include=['datetime64[ns, UTC]']).columns:
df[col] = df[col].apply(lambda x: x.tz_localize(None))
Upvotes: 0
Reputation: 799
To remove timezone from all datetime columns in a DataFrame with mixed columns just use:
for col in df.select_dtypes(['datetimetz']).columns:
df[col] = df[col].dt.tz_localize(None)
if you can't save df to excel file just use this (not delete timezone!):
for col in df.select_dtypes(['datetimetz']).columns:
df[col] = df[col].dt.tz_convert(None)
Upvotes: 9
Reputation: 18978
Following Beatriz Fonseca's suggestion, I ended up doing the following:
from datetime import datetime
df['dates'].apply(lambda x:datetime.replace(x,tzinfo=None))
Upvotes: 4
Reputation: 3872
If your series contains only datetimes, then you can do:
my_series.dt.tz_localize(None)
This will remove the timezone information ( it will not change the time) and return a series of naive local times, which can be exported to excel using to_excel() for example.
Upvotes: 46
Reputation: 863166
Maybe help strip last 6 chars:
print df
datetime
0 2015-12-01 00:00:00-06:00
1 2015-12-01 00:00:00-06:00
2 2015-12-01 00:00:00-06:00
df['datetime'] = df['datetime'].astype(str).str[:-6]
print df
datetime
0 2015-12-01 00:00:00
1 2015-12-01 00:00:00
2 2015-12-01 00:00:00
Upvotes: 13
Reputation: 6661
If it is always the last 6 characters that you want to ignore, you may simply slice your current string:
>>> '2015-12-01 00:00:00-06:00'[0:-6]
'2015-12-01 00:00:00'
Upvotes: -1