Removing all empty elements from a hash / YAML?

Question

How would I go about removing all empty elements (empty list items) from a nested Hash or YAML file?

Answer 1

  validated_params
    .to_h
    .delete_if {|_,v| !v.present? }

Answer 2

in ruby 2.7 there are standard compact and transform_values methods, on the Hash so you can do this like this:

class Hash 
  def deep_compact
    compact.transform_values{|vl| vl.is_a?(Hash) ? vl.deep_compact : vl }
  end
end

It's the neatiest implementation, imho.

Answer 3

compact_blank (Rails 6.1+)

If you are using Rails (or a standalone ActiveSupport), starting from version 6.1, there is a compact_blank method which removes blank values from hashes.

It uses Object#blank? under the hood for determining if an item is blank.

{ a: "", b: 1, c: nil, d: [], e: false, f: true }.compact_blank
# => { b: 1, f: true }

Here is a link to the docs and a link to the relative PR.

A destructive variant is also available. See Hash#compact_blank!.

---

If you need to remove only nil values,

please, consider using Ruby build-in Hash#compact and Hash#compact! methods.

{ a: 1, b: false, c: nil }.compact
# => { a: 1, b: false }

Answer 4

Deep deletion nil values from a hash.

  # returns new instance of hash with deleted nil values
  def self.deep_remove_nil_values(hash)
    hash.each_with_object({}) do |(k, v), new_hash|
      new_hash[k] = deep_remove_nil_values(v) if v.is_a?(Hash)
      new_hash[k] = v unless v.nil?
    end
  end

  # rewrite current hash
  def self.deep_remove_nil_values!(hash)
    hash.each do |k, v|
      deep_remove_nil_values(v) if v.is_a?(Hash)
      hash.delete(k) if v.nil?
    end
  end

Answer 5

If you're using Ruby 2.4+, you can call compact and compact!

h = { a: 1, b: false, c: nil }
h.compact! #=> { a: 1, b: false }

https://ruby-doc.org/core-2.4.0/Hash.html#method-i-compact-21

Answer 6

works for both hashes and arrays

module Helpers
  module RecursiveCompact
    extend self

    def recursive_compact(hash_or_array)
      p = proc do |*args|
        v = args.last
        v.delete_if(&p) if v.respond_to? :delete_if
        v.nil? || v.respond_to?(:"empty?") && v.empty?
      end

      hash_or_array.delete_if(&p)
    end
  end
end

P.S. based on someones answer, cant find

usage - Helpers::RecursiveCompact.recursive_compact(something)

Answer 7

Here is something I have:

# recursively remove empty keys (hashes), values (array), hashes and arrays from hash or array
def sanitize data
  case data
  when Array
    data.delete_if { |value| res = sanitize(value); res.blank? }
  when Hash
    data.delete_if { |_, value| res = sanitize(value); res.blank? }
  end
  data.blank? ? nil : data
end

Answer 8

The recursive version of https://stackoverflow.com/a/14773555/1519240 works, but not with HashWithIndifferentAccess or other classes that are kind of Hash..

Here is the version I am using:

def recursive_compact
  inject({}) do |new_hash, (k,v)|
    if !v.nil?
      new_hash[k] = v.kind_of?(Hash) ? v.recursive_compact : v
    end
    new_hash
  end
end

kind_of?(Hash) will accept more classes that are like a Hash.

You can also replace inject({}) by inject(HashWithIndifferentAccess.new) if you want to access the new hash using both symbol and string.

Answer 9

Try this to remove nil

hash = { a: true, b: false, c: nil }
=> {:a=>true, :b=>false, :c=>nil}
hash.inject({}){|c, (k, v)| c[k] = v unless v.nil?; c}
=> {:a=>true, :b=>false}

Answer 10

Rails 4.1 added Hash#compact and Hash#compact! as a core extensions to Ruby's Hash class. You can use them like this:

hash = { a: true, b: false, c: nil }
hash.compact                        
# => { a: true, b: false }
hash                                
# => { a: true, b: false, c: nil }
hash.compact!                        
# => { a: true, b: false }
hash                                
# => { a: true, b: false }
{ c: nil }.compact                  
# => {}

Heads up: this implementation is not recursive. As a curiosity, they implemented it using #select instead of #delete_if for performance reasons. See here for the benchmark.

In case you want to backport it to your Rails 3 app:

# config/initializers/rails4_backports.rb

class Hash
  # as implemented in Rails 4
  # File activesupport/lib/active_support/core_ext/hash/compact.rb, line 8
  def compact
    self.select { |_, value| !value.nil? }
  end
end

Answer 11

Ruby's Hash#compact, Hash#compact! and Hash#delete_if! do not work on nested nil, empty? and/or blank? values. Note that the latter two methods are destructive, and that all nil, "", false, [] and {} values are counted as blank?.

Hash#compact and Hash#compact! are only available in Rails, or Ruby version 2.4.0 and above.

Here's a non-destructive solution that removes all empty arrays, hashes, strings and nil values, while keeping all false values:

(blank? can be replaced with nil? or empty? as needed.)

def remove_blank_values(hash)
  hash.each_with_object({}) do |(k, v), new_hash|
    unless v.blank? && v != false
      v.is_a?(Hash) ? new_hash[k] = remove_blank_values(v) : new_hash[k] = v
    end
  end
end

A destructive version:

def remove_blank_values!(hash)
  hash.each do |k, v|
    if v.blank? && v != false
      hash.delete(k)
    elsif v.is_a?(Hash)
      hash[k] = remove_blank_values!(v)
    end
  end
end

Or, if you want to add both versions as instance methods on the Hash class:

class Hash
  def remove_blank_values
    self.each_with_object({}) do |(k, v), new_hash|
      unless v.blank? && v != false
        v.is_a?(Hash) ? new_hash[k] = v.remove_blank_values : new_hash[k] = v
      end
    end
  end

  def remove_blank_values!
    self.each_pair do |k, v|
      if v.blank? && v != false
        self.delete(k)
      elsif v.is_a?(Hash)
        v.remove_blank_values!
      end
    end
  end
end

Other options:

• Replace v.blank? && v != false with v.nil? || v == "" to strictly remove empty strings and nil values
• Replace v.blank? && v != false with v.nil? to strictly remove nil values
• Etc.

EDITED 2017/03/15 to keep false values and present other options

Answer 12

class Hash   
  def compact
    def _empty?(val)
      case val
      when Hash     then val.compact.empty?
      when Array    then val.all? { |v| _empty?(v) }
      when String   then val.empty?
      when NilClass then true
      # ... custom checking 
      end
    end

    delete_if { |_key, val| _empty?(val) }   
  end 
end

Answer 13

Could be done with facets library (a missing features from standard library), like that:

require 'hash/compact'
require 'enumerable/recursively'
hash.recursively { |v| v.compact! }

Works with any Enumerable (including Array, Hash).

Look how recursively method is implemented.

Answer 14

You can use Hash#reject to remove empty key/value pairs from a ruby Hash.

# Remove empty strings
{ a: 'first', b: '', c: 'third' }.reject { |key,value| value.empty? } 
#=> {:a=>"first", :c=>"third"}

# Remove nil
{a: 'first', b: nil, c: 'third'}.reject { |k,v| v.nil? } 
# => {:a=>"first", :c=>"third"}

# Remove nil & empty strings
{a: '', b: nil, c: 'third'}.reject { |k,v| v.nil? || v.empty? } 
# => {:c=>"third"}

Answer 15

I made a deep_compact method for this that recursively filters out nil records (and optionally, blank records as well):

class Hash
  # Recursively filters out nil (or blank - e.g. "" if exclude_blank: true is passed as an option) records from a Hash
  def deep_compact(options = {})
    inject({}) do |new_hash, (k,v)|
      result = options[:exclude_blank] ? v.blank? : v.nil?
      if !result
        new_value = v.is_a?(Hash) ? v.deep_compact(options).presence : v
        new_hash[k] = new_value if new_value
      end
      new_hash
    end
  end
end

Answer 16

I believe it would be best to use a self recursive method. That way it goes as deep as is needed. This will delete the key value pair if the value is nil or an empty Hash.

class Hash
  def compact
    delete_if {|k,v| v.is_a?(Hash) ? v.compact.empty? : v.nil? }
  end
end

Then using it will look like this:

x = {:a=>{:b=>2, :c=>3}, :d=>nil, :e=>{:f=>nil}, :g=>{}}
# => {:a=>{:b=>2, :c=>3}, :d=>nil, :e=>{:f=>nil}, :g=>{}} 
x.compact
# => {:a=>{:b=>2, :c=>3}}

To keep empty hashes you can simplify this to.

class Hash
  def compact
    delete_if {|k,v| v.compact if v.is_a?(Hash); v.nil? }
  end
end

Answer 17

In Simple one liner for deleting null values in Hash,

rec_hash.each {|key,value| rec_hash.delete(key) if value.blank? } 

Answer 18

our version: it also cleans the empty strings and nil values

class Hash

  def compact
    delete_if{|k, v|

      (v.is_a?(Hash) and v.respond_to?('empty?') and v.compact.empty?) or
          (v.nil?)  or
          (v.is_a?(String) and v.empty?)
    }
  end

end

Answer 19

You could add a compact method to Hash like this

class Hash
  def compact
    delete_if { |k, v| v.nil? }
  end
end

or for a version that supports recursion

class Hash
  def compact(opts={})
    inject({}) do |new_hash, (k,v)|
      if !v.nil?
        new_hash[k] = opts[:recurse] && v.class == Hash ? v.compact(opts) : v
      end
      new_hash
    end
  end
end

Answer 20

Use hsh.delete_if. In your specific case, something like: hsh.delete_if { |k, v| v.empty? }

Answer 21

I know this thread is a bit old but I came up with a better solution which supports Multidimensional hashes. It uses delete_if? except its multidimensional and cleans out anything with a an empty value by default and if a block is passed it is passed down through it's children.

# Hash cleaner
class Hash
    def clean!
        self.delete_if do |key, val|
            if block_given?
                yield(key,val)
            else
                # Prepeare the tests
                test1 = val.nil?
                test2 = val === 0
                test3 = val === false
                test4 = val.empty? if val.respond_to?('empty?')
                test5 = val.strip.empty? if val.is_a?(String) && val.respond_to?('empty?')

                # Were any of the tests true
                test1 || test2 || test3 || test4 || test5
            end
        end

        self.each do |key, val|
            if self[key].is_a?(Hash) && self[key].respond_to?('clean!')
                if block_given?
                    self[key] = self[key].clean!(&Proc.new)
                else
                    self[key] = self[key].clean!
                end
            end
        end

        return self
    end
end

Answer 22

This one would delete empty hashes too:

swoop = Proc.new { |k, v| v.delete_if(&swoop) if v.kind_of?(Hash);  v.empty? }
hsh.delete_if &swoop