CODEWITHSUNDEEP
phputf-8
Ikhlak S.
Ikhlak S.

Reputation: 9034

Get String After a Certain Character While Avoiding UTF-8 Bugs

I have done my research before posting, but cannot find an answer to this. How do I get the portion of a string after a certain character?

For example, for the string:

gallery/user/profile/img_904.jpg

I want to return:

img_904.jpg

I am also concerned about bugs with basename() regarding UTF-8 filenames containing Asian characters.

Upvotes: 3

Views: 90

Answers (3)

Will
Will

Reputation: 24709

In this case, you can just use the basename() function:

php > $path = 'gallery/user/profile/img_904.jpg';
php > echo basename($path);
img_904.jpg

As a more general example, if you wanted to get the part of a string after the last |, for example, you could use an approach like this:

php > $string = 'Field 1|Field 2|Field 3';
php > echo substr(strrchr($string, '|'), 1);
Field 3

Or even:

php > $string = 'Field 1|Field 2|Field 3';
php > echo substr($string, strrpos($string, '|') + 1);
Field 3

Edit

You noted problems with UTF-8 handling in basename(), which is a problem I have run into as well with several versions of PHP. I use the following code as a workaround on UTF-8 paths:

/**
 * Returns only the file component of a path. This is needed due to a bug
 * in basename()'s handling of UTF-8.
 *
 * @param string $path Full path to to file.
 * @return string Basename of file.
 */
function getBasename($path)
{
    $parts = explode('/', $path);

    return end($parts);
}

From the PHP basename() documentation:

Note: basename() is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale() function.

Upvotes: 3

John Pangilinan
John Pangilinan

Reputation: 1031

$path = gallery/user/profile/img_904.jpg;
$temp = explode('/', $path);
$filename = $temp[count($temp)-1];

Upvotes: 0

Kshitij Soni
Kshitij Soni

Reputation: 394

<?php

$path = 'gallery/user/profile/img_904.jpg';
$filename = substr(strrchr($path, "/"), 1);
echo $filename; 


?>

This will help you ..

Upvotes: 2

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