CODEWITHSUNDEEP
c#sftpwinscpwinscp-net
Javier Salas
Javier Salas

Reputation: 1188

How to remove "." and ".." files from remote directory with C# and WinSCP

I'm trying to get the files count from a remote directory using a SFTP connection, but I'm getting . and .. and these are counted these dots like a files, I have 2 files in the remote directory but is counting 4 files including . and ...

Someone can help me how to solve this?

This is my code:

filesCount = session.ListDirectory(DataFile.sRemoteDirectory).Files.Count;

Thanks!

Upvotes: 3

Views: 2609

Answers (5)

Martin Prikryl
Martin Prikryl

Reputation: 202504

The . and .. are references to this and parent directories respectively on most file systems.

To filter them, you can use new properties .IsThisDirectory and .IsParentDirectory of the RemoteFileInfo class:

filesCount =   
    session.ListDirectory(DataFile.sRemoteDirectory).Files
        .Where(file => !file.IsThisDirectory && !file.IsParentDirectory).Count();

Note that you have to use the Enumerable.Count() extension method, instead of the ICollection.Count property as the result of the Enumerable.Where() is the IEnumerable, not the Collection anymore.

Or to make it even easier, use the Session.EnumerateRemoteFiles() method, which with the EnumerationOptions.None option is functionally equivalent to the Session.ListDirectory(), just that it excludes the . and ...

filesCount =
    session.EnumerateRemoteFiles(
        DataFile.sRemoteDirectory, null, EnumerationOptions.None).Count();

If you want to filter all directories, use:

filesCount =   
    session.ListDirectory(DataFile.sRemoteDirectory).Files
        .Where(file => !file.IsDirectory).Count();

Upvotes: 2

Sumner Evans
Sumner Evans

Reputation: 9155

According to the WinSCP documentation:

You can use Session.EnumerateRemoteFiles method instead, if you want to:

  • List only files matching a wildcard;
  • List the files recursively;
  • Have references to this (.) and parent (..) directories be excluded form the listing.

So it appears that you should change your code to do something more like this:

filesCount = 0; 
filesCount = session.EnumerateRemoteFiles(DataFile.sRemoteDirectory).Files.Count();                
session.Close();

Upvotes: 5

Alex Skalozub
Alex Skalozub

Reputation: 2576

Despite its naming, Files collection contains not only files, but all directory entries, including current and parent directory references.

If you want to count only files, filter them by IsDirectory property:

var filesCount = session.ListDirectory(dir).Files.Where(x => !x.IsDirectory).Count();

There's also IsParentDirectory and IsThisDirectory properties in the latest versions to filter ".." and "." cases without name comparison.

Upvotes: 0

Richard Vasquez
Richard Vasquez

Reputation: 197

Try session.EnumerateRemoteFiles instead.

Upvotes: 0

Lewis Taylor
Lewis Taylor

Reputation: 728

Instead of using ListDirectory you can use EnumerateRemoteFiles and it wont include ".." and "."

"." and ".." mean this directory and parent directory respectively.

Upvotes: 3

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