CODEWITHSUNDEEP
pythonregexpython-3.x
Hello lad
Hello lad

Reputation: 18790

Regex How to match Empty

I have log structure looks like

a b c|

so for example:

Mozilla 5.0 white|

should be matched/extracted to sth like

a: Mozilla, b: 5.0, c: white

but there is an entry in my log is:

iOS|

which can be explained as

a:iOS, b:null, c:null

I am using python3 re, doing match with named group ?P

is there any way to achieve this?

Upvotes: 0

Views: 220

Answers (2)

Anders
Anders

Reputation: 2316

>>> m = re.match(r"(?P<a>[^\s]+)(\s+(?P<b>[^\s]+))?(\s+(?P<c>[^\s]+))?\s*\|")

>>> m.groups()
('iOS', None, None)
>>> m.groupdict()
{'c': None, 'a': 'iOS', 'b': None}

>>> m = re.match(r"(?P<a>[^\s]+)(\s+(?P<b>[^\s]+))?(\s+(?P<c>[^\s]+))?\s*\|")

>>> m.groups()
('Mozilla', ' 5.0', ' white')
>>> m.groupdict()
{'c': 'white', 'a': 'Mozilla', 'b': '5.0'}

UPDATE:

I noticed that the previous version included spaces in the returned groups - I had factored the \s+ into the (?P<>...) to save a couple bytes, but it had that side effect. So I fixed that and also made it tolerant of spaces before the final '|'

Upvotes: 2

Kasravnd
Kasravnd

Reputation: 107347

You can put your patterns in a list like following :

>>> pattern = ['a', 'b', 'c']

Then use re.findall() to find all the relative parts, then use zip and dict to create the relative dictionary:

>>> s = "IOS|"
>>> dict(zip(pattern,re.findall('([^\s]+)?\s?([^\s]+)?\s?([^\s]+)?\|',s)[0]))
{'a': 'IOS', 'c': '', 'b': ''}
>>> 
>>> s = "Mozilla 5.0 white|"
>>> 
>>> dict(zip(pattern,re.findall('([^\s]+)?\s?([^\s]+)?\s?([^\s]+)?\|',s)[0]))
{'a': 'Mozilla', 'c': 'white', 'b': '5.0'}

Upvotes: 2

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