CODEWITHSUNDEEP
pythonfabric
Joff
Joff

Reputation: 12187

fabric returning 127 with "source" command

I just can't figure out why this is happening...

in my fabric file I have this...

def func():
    local("source ../venv/bin/activate")

It is returning 127 on the source command and I am not sure why, when i try to run source in my terminal manually it works. When I try a different command in fabric, like...

local("echo 'foo'")

it also works. Why would source be causing problems? I can't see any reason why this would be happening.

Upvotes: 2

Views: 636

Answers (1)

jumbopap
jumbopap

Reputation: 4137

source is unknown by sh. If you want to run a command in the context of a virtual environment, use Fabric's context managers and run the activate binary without source. I've adapted from this answer.

from __future__ import with_statement
from fabric.api import *
from contextlib import contextmanager as _contextmanager

env.activate = '. ./.env/bin/activate'

@_contextmanager
def virtualenv():
    with prefix(env.activate):
        yield

def deploy():
    with virtualenv():
        local('echo hello world!')

Upvotes: 4

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