CODEWITHSUNDEEP
arraysswiftswitch-statementtuples
Cody Weaver
Cody Weaver

Reputation: 4886

Swift switch with range

I have an Array of Int and want to find what range each instance is in.

let array: [Int] = [35,34,33,32,31,30,28,27,26,25,24,23,7,6,5,4,3,2,1]

I have another Array of Tuple's of Int

let tupleArray: [(Int, Int)] = [(35,30),(28,22), (21,15), (14,8), (7,0)]

I am using a Switch to iterate over them.

for a in 0..<array.count {
    var iteration: Int = 0
    switch array[a] {
    case tupleArray[iteration].0...tupleArray[iteration].1:
        print("Within Range")
    default:
        print("Next iteration")
        repeat {
             iteration++ 
        } while tupleArray[iteration].0 < array[a]
    } 
}

My question is how can I make it so that there is just that one case and then in the default it keeps going until it finds the range that the next number would fall into. The current code works completely find until there is a gap of more than iteration. So for 35-30 and 28-23 it works fine but then it goes to 21-15

Upvotes: 2

Views: 631

Answers (1)

Code Different
Code Different

Reputation: 93151

I'm surprised that you can run the code at all. In my Xcode 7.1, it gives a runtime error:

fatal error: Can't form Range with end < start

...because your tuples are in (end, start) form rather than the other way around.

If you want to find what range each item in array belong to, try this:

for a in array {
    if let range = (tupleArray.filter { $0.1 <= a && a <= $0.0 }).first {
        print("\(a) is within \(range)")
    } else {
        print("Cannot find a range for \(a)")
    }
}

Upvotes: 1

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