CODEWITHSUNDEEP
javaldapjndi
Nivek
Nivek

Reputation: 729

LDAP user password authentication using JNDI

public static void main(String[] args)
{
    String INITCTX = "com.sun.jndi.ldap.LdapCtxFactory";
    String MY_HOST = "ldap://Localhost:1389";
    String MGR_DN = "cn=John,ou=Users,o=IT,dc=QuizPortal";
    String MGR_PW = "password";           

    //Identify service provider to use
    Hashtable env = new Hashtable();
    env.put(Context.INITIAL_CONTEXT_FACTORY, INITCTX);
    env.put(Context.PROVIDER_URL, MY_HOST);
    env.put(Context.SECURITY_AUTHENTICATION, "simple");
    env.put(Context.SECURITY_PRINCIPAL, MGR_DN);
    env.put(Context.SECURITY_CREDENTIALS, MGR_PW);

    try
    {
        // Create the initial directory context
        InitialDirContext initialContext = new InitialDirContext(env);

        System.out.println("Context Sucessfully Initialized");
    }
    catch(Exception e)
    {
        System.err.println(e);
    }
}

I would like to ask when I set the MGR_DN = "cn=John,ou=Users,o=IT,dc=QuizPortal" to MGR_DN = "uid=103,ou=Users,o=IT,dc=QuizPortal". Basically changing from cn to uid, I would encounter an error 

javax.naming.AuthenticationException: [LDAP: error code 49 - Invalid Credentials]

I am authenticated when is specified as cn=John but not uid=103. Am I not allowed to specify by uid?

Upvotes: 9

Views: 16344

Answers (3)

Bruno
Bruno

Reputation: 122759

If you don't know the exact DN in advance, you should do a search in the LDAP directory first. This can be done more or less like this (make sure you catch the relevant exceptions):

Properties env = new Properties();
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, ldapServerUrl);
env.put(Context.SECURITY_AUTHENTICATION, "none");

SearchControls searchCtrls = new SearchControls();
searchCtrls.setReturningAttributes(new String[] {});
searchCtrls.setSearchScope(SearchControls.SUBTREE_SCOPE);

String filter = "(&(cn=" + identifier + "))";

DirContext ctx = null;
ctx = new InitialDirContext(env);
NamingEnumeration<SearchResult> answer = ctx.search(
   ldapBaseDN, filter, searchCtrls);

String fullDN = null;
if (answer.hasMore()) {
    fullDN = answer.next().getNameInNamespace();

    ctx.close();
    ctx = null;

    env.put(Context.SECURITY_AUTHENTICATION, "simple");
    env.put(Context.SECURITY_PRINCIPAL, fullDN);
    env.put(Context.SECURITY_CREDENTIALS, password);

    ctx = new InitialDirContext(env);
    return true;
}
// Exception otherwise ...

Here, the search filter is "(&(cn=" + identifier + "))" (so, for example (&(cn=John))), but you could use the uid instead. Uniqueness of the results depends on the configuration of the LDAP server. The base DN also depends on the way it's set up (it could be ou=Users,o=IT,dc=QuizPortal in your example).

Upvotes: 8

Andreas Dolk
Andreas Dolk

Reputation: 114837

It looks like a server configuration issue. Here's a similar problem including a solution. Basically you'll have to specify whether to use uid or cn for authentication in ldap-authentication.properties.

Upvotes: 2

user207421
user207421

Reputation: 311054

You have to specify the DN or distinguished name. That's the name the user is bound as in the directory. You can't just select any chain of attributes. If your users are bound via the 'cn' attribute then only the 'cn' attribute is part of the DN.

Upvotes: 4

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