CODEWITHSUNDEEP
carraysfunctionpointersmultidimensional-array
paxie
paxie

Reputation: 197

Printing 2D array of chars with number representing line at the beginning

The following function : 

char **fill(char **array, int *size) {

    int i,j;

    for ( i = 0; i < *size; i++ ) {
        for (j = 0; j < *size; j++ ) {
            array[i][j] = '-';  
        }   
    }   

    return array;
}

For input: 5

Gives output:

    - - - - - 
    - - - - - 
    - - - - - 
    - - - - - 
    - - - - -

How to edit the code to get output like this : 

   0 - - - - - 
   1 - - - - - 
   2 - - - - - 
   3 - - - - - 
   4 - - - - -

"array" in my function is 2D array of chars of given size n. When i get input of n i tried to allocate every line for n + 1 chars not for n and make the function like this : 

char **fill(char **array, int *size) {

        int i,j;

        for ( i = 0; i < *size; i++ ) {
            array[i][0] = 'i';
            for (j = 1; j < ( *size + 1 ); j++ ) {
                array[i][j] = '-';  
            }   
        }   

        return array;
    }

But it does not work.

Input : 5 Output : 

   i - - - - - 
   i - - - - - 
   i - - - - - 
   i - - - - - 
   i - - - - -

Upvotes: 1

Views: 39

Answers (2)

Rabbid76
Rabbid76

Reputation: 211135

You are printing the character 'i', but you have to print a character from '0' to '9':

 for ( i = 0; i < *size; i++ ) {
        array[i][0] = '0' + i; // <-
        for (j = 1; j < ( *size + 1 ); j++ ) {
            array[i][j] = '-';  
        }   
    }

Characters from '0' to '9' have ASCII codes from 48 to 57. '0' + i means the character with ASCII code 48+i. The above code works from 0 to 9. If i==10, it prints ':', because ':' is the character with ASCII code 58 (48+10). See ASCII table and question Char - ASCII relation.

Upvotes: 1

autistic
autistic

Reputation: 15642

I think by array[i][0] = 'i'; you meant to write array[i][0] = '0'+i;...

Keep in mind this is modifying the array. If you wanted to print the array without modifying it, we'd need to see that code.

Upvotes: 0

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