CODEWITHSUNDEEP
arraysbash
Omar Ali
Omar Ali

Reputation: 85

convert a line into array and print elements of array as variables in bash

I am new in linux and I try reading a text file line by line. The lines are numbers. I want to add each line in an array and consider each number as a variable. My trial is as below:
Example of txt file:

1976   1   0  0.00    0.    68.    37.     0.   105.  0.14 0.02    4.3    1.1    2.2

What I need:
Putting each number in a variable. for example a = 1976 and b = 1 etc...
My code:

IFS=$'\n'
for next in `cat $filename`
do

line=$next

echo ${line[0]}
done

Result:

1976   1   0  0.00    0.    68.    37.     0.   105.  0.14 0.02    4.3    1.1    2.2

Upvotes: 0

Views: 654

Answers (2)

bogomips
bogomips

Reputation: 21

# Add each line to Array
readarray -t aa < $filename
# Put each line into variables using Here String
for l in "${aa[@]}"; do
  read a b c <<< $l;     # Example using 3 variables, could be as many as on line
  # Do whatever has to be done with a, b, c, etc
done

Upvotes: 0

aleksanderzak
aleksanderzak

Reputation: 1172

It's quite easy to store each value in an array. Here is an example:

while read -r -a line
do
 echo "${line[0]}"
 echo "${line[1]}"
 echo "${line[2]}"
done < $filename

-a line splits the input-line into words (white space seperated by default) and store the results in line array.

A snippet from read man:

-a Each name is an indexed array variable (see Arrays above).

You man not need the '-r' option. It basically make read to treat \ as nothing special in the input.

Upvotes: 1

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