Reputation: 21573
A string maybe this
ipath= "./data/NCDC/上海/虹桥/9705626661750dat.txt"
or this
ipath = './data/NCDC/ciampino/6240476818161dat.txt'
How do I know the first string contains chinese?
I find this answer maybe helpful: Find all Chinese text in a string using Python and Regex
but it didn't work out:
import re
ipath= "./data/NCDC/上海/虹桥/9705626661750dat.txt"
re.findall(ur'[\u4e00-\u9fff]+', ipath) # => []
Upvotes: 25
Views: 49066
Reputation: 18621
Use \p{Han}
regex with PyPi regex
:
import regex
ipath = "./data/NCDC/上海/虹桥/9705626661750dat.txt"
print(regex.findall(r'\p{Han}+', ipath) )
# => ['上海', '虹桥']
See Python proof.
The regex.search
is enough to detect:
if regex.search(r'\p{Han}', ipath):
print(f'"{ipath}" contains Chinese!')
Upvotes: 12
Reputation: 5193
The matched string should be unicode as well
>>> import re
>>> ipath= u"./data/NCDC/上海/虹桥/9705626661750dat.txt"
>>> re.findall(r'[\u4e00-\u9fff]+', ipath)
[u'\u4e0a\u6d77', u'\u8679\u6865']
Upvotes: 29
Reputation: 1653
Using these codepoint ranges, we can write an is_cjk
function:
# list of cjk codepoint ranges
# tuples indicate the bottom and top of the range, inclusive
cjk_ranges = [
( 0x4E00, 0x62FF),
( 0x6300, 0x77FF),
( 0x7800, 0x8CFF),
( 0x8D00, 0x9FCC),
( 0x3400, 0x4DB5),
(0x20000, 0x215FF),
(0x21600, 0x230FF),
(0x23100, 0x245FF),
(0x24600, 0x260FF),
(0x26100, 0x275FF),
(0x27600, 0x290FF),
(0x29100, 0x2A6DF),
(0x2A700, 0x2B734),
(0x2B740, 0x2B81D),
(0x2B820, 0x2CEAF),
(0x2CEB0, 0x2EBEF),
(0x2F800, 0x2FA1F)
]
def is_cjk(char):
char = ord(char)
for bottom, top in cjk_ranges:
if char >= bottom and char <= top:
return True
return False
Which we can then use to process text, using functions like filter
, any
, all
, and map
to process the text character-by-character, or compose more complex functions:
txt = "./data/NCDC/上海/虹桥/9705626661750dat.txt"
txt_sanitized = "./data/NCDC/9705626661750dat.txt"
any(map(is_cjk, txt)) # True
any(map(is_cjk, txt_sanitized)) # False
''.join(filter(is_cjk, txt)) # '上海虹桥'
Note that the CJK ranges will include not only Chinese characters but also may include Korean and Japanese characters. For more complex usage, try a dedicated library like cjklib
.
Upvotes: 5
Reputation: 1250
According to this question, the range should be [\u2E80-\u2FD5\u3190-\u319f\u3400-\u4DBF\u4E00-\u9FCC]
Upvotes: 2
Reputation: 22453
And for those of us who don't care for re
:
>>> ipath= u"./data/NCDC/上海/虹桥/6240476818161dat.txt"
>>> for i in range(len(ipath)):
... if ipath[i] > u'\u4e00' and ipath[i] < u'\u9fff':
... print ipath[i]
...
上
海
虹
桥
Edit: for the full list of Chinese characters this SO link is worth looking at as the range U+4E00..U+9FFF is not complete. What's the complete range for Chinese characters in Unicode?
Upvotes: 5
Reputation: 78750
If you just want to know whether there is a chinese character in your string you don't need re.findall
, use re.search
and the fact that match objects are truthy.
>>> import re
>>> ipath= u'./data/NCDC/上海/虹桥/9705626661750dat.txt'
>>> ipath2 = u'./data/NCDC/ciampino/6240476818161dat.txt'
>>> for x in (ipath, ipath2):
... if re.search(u'[\u4e00-\u9fff]', x):
... print 'found chinese character in ' + x
...
found chinese character in ./data/NCDC/上海/虹桥/9705626661750dat.txt
Upvotes: 12
Reputation: 414585
''
is a bytestring on Python 2. Either add from __future__ import unicode_literals
at the top of the module or use unicode literals: u''
:
>>> import re
>>> ipath= u"./data/NCDC/上海/虹桥/9705626661750dat.txt"
>>> re.findall(ur'[\u4e00-\u9fff]+', ipath)
[u'\u4e0a\u6d77', u'\u8679\u6865']
Upvotes: 1
Reputation: 67978
import re
ipath= raw_input()
print re.findall(ur'[\u4e00-\u9fff]+', ipath.decode("utf-8"))
Output:./data/NCDC/上海/虹桥/9705626661750dat.txt
[u'\u4e0a\u6d77', u'\u8679\u6865']
You need to decode the input to make it unicode.
or
import re
ipath= unicode(raw_input(),encoding="utf-8")
print re.findall(ur'[\u4e00-\u9fff]+', ipath)
Upvotes: 1