Reputation: 13
I have lots of files in a directory and I want to list all files in a specific format by creating date order (newer files first)
I can do this with stat
and sort
in the directory of files:
Commands:
cd /path
stat -c '%.19y %n' * | sort -nr
Output:
2014-01-25 16:44:52 Filename1.txt
2014-01-24 16:34:17 Filename2.txt
It is fine. This is what I want exactly.
But when I try to run outside of the directory, command shows filenames with /path
Commands:
cd /
stat -c '%.19y %n' /path/* | sort -nr
Output:
2014-01-25 16:44:52 /path/Filename1.txt
2014-01-24 16:34:17 /path/Filename2.txt
How can I list file names without path?
Upvotes: 0
Views: 485
Reputation: 11216
Provided you have GNU find, you can use that instead
find /path -printf '%TY-%Tm-%Td %TH:%TM:%.2TS %f\n'
2015-10-12 04:54:24 file
Upvotes: 1