Reputation: 13
struct Tree{
char string[30];
int hmanyt;
struct Tree * left;
struct Tree * right;
};
typedef struct Tree * drzewo;
void printftree(drzewo* korzen)
{
if((*korzen)->left != NULL)
printftree(&((*korzen)->left));
printf("%s(%d)\n",(*korzen)->string,(*korzen)->hmanyt);
if(strcmp((*korzen)->string,"boril\0")==0)
(((*korzen)->right)->left)->left=NULL;
if((*korzen)->right != NULL)
printftree(&((*korzen)->right));
return ;
}
void erease(drzewo* korzen)
{
if((*korzen)->left==NULL && (*korzen)->right==NULL)
{
*korzen=NULL;
free (*korzen);
return ;
}
else
{
if((*korzen)->left !=NULL)
{
erease(&((*korzen)->left));
(*korzen)->left=NULL;
free((*korzen)->left);
}
if((*korzen)->right !=NULL)
{
erease(&((*korzen)->right));
(*korzen)->right=NULL;
free((*korzen)->right);
}
}
*korzen=NULL;
free(*korzen);
return ;
}
void add(drzewo* korzen,char word[])
{
while(*korzen!=NULL)
{
if(strcmp((*korzen)->string,word)==0) {
((*korzen)->hmanyt)++;
return; }
else if(strcmp((*korzen)->string,word)<0) {
korzen=&((*korzen)->right); }
else if(strcmp((*korzen)->string,word)>0) {
korzen=&((*korzen)->left);
}
}
*korzen=(drzewo) malloc(sizeof(drzewo));
strcpy(((*korzen)->string),word);
printf("%p",(*korzen)->left);
printf("%p\n",(*korzen)->right);
(*korzen)->hmanyt=1;
return;
}
int main()
{
drzewo korzen =NULL;
char *words[10]={"alfabet","borixon","aaaaaa","zombie","bobas","kamil","agnieszka","kokos","zamach"};
for(int i=0;i<9;i++)
add(&korzen,words[i]);
printf("test1\n");
printftree(&korzen);
printf("test");
erease(&korzen);
return 0;
}
So this is my implementation of binary tree. Which loads 10 words to the tree . Sadly during 'printing' this tree I came across a problem which is core dumped. I don't know why but one of the structurs "has" (*korzen)->left that isn't NULL, my funcion wants to acess it,and the core dumped appears. After adding two lines
if(strcmp((*korzen)->string,"boril\0")==0)
(((*korzen)->right)->left)->left=NULL;
it works fine, but I don't know why i have this issue. Another issue is that despite having such a line as:
(*korzen)->hmanyt=1;
Afterall it doesn't have this value ... (only first word has hmanyt==1) . Help would be really appreciated.
Upvotes: 1
Views: 155
Reputation: 210998
It is a bad idea to assign NULL
to a pointer which you want to free
. Change place of *korzen=NULL;
and free(*korzen);
in your function erease
:
Adapt your function erease
like this:
void erease(drzewo* korzen)
{
if ( *korzen == NULL )
return;
if( (*korzen)->left !=NULL )
{
erease(&((*korzen)->left)); // (*korzen)->left is freed in erease
}
if( (*korzen)->right !=NULL )
{
erease(&((*korzen)->right)); // (*korzen)->right is freed in erease
}
free(*korzen);
*korzen=NULL;
return;
}
If you insert a new node in your tree you have to initialize its childs (*korzen)->left
and (*korzen)->right
with NULL
. Further the type of drzewo
is struct Tree*
, so sizeof(drzewo)
gives the size of a pointer not the size of struct Tree
.
void add(drzewo* korzen,char word[])
{
while( *korzen != NULL )
{
int cmp = strcmp( ( *korzen )->string, word );
if ( cmp == 0 )
{
((*korzen)->hmanyt)++;
return;
}
else if( cmp<0 ) {
korzen=&((*korzen)->right);
}
else if (cmp>0 ) {
korzen=&((*korzen)->left);
}
}
// allocate new node and initiialize
*korzen=malloc(sizeof(struct Tree)); // allocat sizeof struct Tree ( not sizeof pointer to Tree)
( *korzen )->left = NULL; // <- left child is null
( *korzen )->right = NULL; // <- right child is null
strcpy(((*korzen)->string),word);
(*korzen)->hmanyt=1;
return;
}
Finally your function printftree
:
void printftree(drzewo* korzen)
{
if ( *korzen == NULL )
return;
if( (*korzen)->left != NULL)
printftree(&((*korzen)->left));
printf("%s(%d)\n",(*korzen)->string,(*korzen)->hmanyt);
if((*korzen)->right != NULL)
printftree(&((*korzen)->right));
return ;
}
Upvotes: 1