CODEWITHSUNDEEP
clinuxbashshellgo
scott
scott

Reputation: 1637

What are the ways to find the session leader or the controlling TTY of a process group in Linux?

This is not a language specific question, although I am using golang at the moment.

I am writing a command line program, and I wanted to find the real UID of the program.(By realUID, I meant, if the user did a sudo, the effective uid changes, but the real uid would be the same as the user's.)

I tried the first way, using

cmdOut []byte
cmdOut, _ = exec.Command("tty").Output()

but it returns the output not a tty, when I run the program from my shell. Chances are that this might be getting executed in a separate forked shell that is detached from a tty (again, just a wild guess).

I tried the second way using os.Getppid() to get the parent pid, but in reality, when running sudo, it forks again, and it is giving the parent pid of the sudo process(16031 in the below case, whereas I am looking to grab 3393 instead.). (Pasting the process hierarchy from pstree output) /usr/bin/termin(3383)-+-bash(3393)---sudo(16031)---Myprogram(16032), so effectively I am not able to get the session leader process, but just the parent pid.

Can someone guide me on how do I implement this functionality using either of this method?

Upvotes: 3

Views: 994

Answers (1)

sheikh_anton
sheikh_anton

Reputation: 3452

Edit: sudo set's $SUDO_USER environment variable, but it will help just with one sudo, i.e. if there was something like sudo sudo -u nobody your-program, $SUDO_USER will be set to "root". And there is $SUDO_UID too.

Old answer: How about exec.Command("who am i").Output() ? (won't work, still needs a tty).

Upvotes: 2

Related Questions