Reputation: 1029
I have an RDD[(String, (Iterable[Int], Iterable[Coordinate]))]
What I would like to do, is to break the Iterable[Int]
to tuples, that each one will be like (String,Int,Iterable[Coordinate])
For an example, I would like to transform:
('a',<1,2,3>,<(45.34,32.33),(45.36,32.34)>)
('b',<1>,<(46.64,32.66),(46.67,32.71)>)
to
('a',1,<(45.34,32.33),(45.36,32.34)>)
('a',2,<(45.34,32.33),(45.36,32.34)>)
('a',3,<(45.34,32.33),(45.36,32.34)>)
('b',1,<(46.64,32.66),(46.67,32.71)>)
How is done is Scala?
Upvotes: 2
Views: 828
Reputation: 8866
Try to use flatMap:
rdd.flatMap {case (v, i1, i2) => i1.map(i=>(v, i, i2)}
Upvotes: 6