CODEWITHSUNDEEP
linuxbashalias
brain storm
brain storm

Reputation: 31252

setting up variables in alias is not working

I want my alias to pick up variables that I pass in commandLine:

For example, startdocker 004 should execute the following

docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar:004

(004 is the tag I am passing in commandLine).

I tried the following in my .bashrc (sourced after the change).

alias startdocker='function dockerStartTag(){ echo "docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1";};dockerStartTag'

when I run startdocker 004, It is not picking up 004. It is empty and hence defaults to "latest" by docker.

what is the correct way to do it? what am I doing wrong?

Thanks

EDIT

I don't want to echo but execute the command.

The correct answer is provided below

Upvotes: 0

Views: 39

Answers (1)

chrisaycock
chrisaycock

Reputation: 37930

There's no reason to put a function inside an alias. Just do

function startdocker(){ echo "docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1"; }

This now works on my system:

$ startdocker 004
docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: 004

And to actually run it, we just need:

function startdocker(){ docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1; }

Upvotes: 2

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