CODEWITHSUNDEEP
pythonprinting
Aleksa Kojadinovic
Aleksa Kojadinovic

Reputation: 337

Looping inside print()

I have a dictionary that contains 9 items, it's called users. Now would it be possible to do this, which is completely functional:

for x in range (0, 9):
    print users[x]

In one line of code with something like

print users[x for x in range (0, 9)]

That gives syntax error. So is it possible to do it this way or maybe I need to use lambda functions or something? Thanks

Upvotes: 0

Views: 61

Answers (3)

Clodion
Clodion

Reputation: 1017

Well, you can write: 

print [users[k] for k in users.keys()]

Upvotes: 0

Ivan Semochkin
Ivan Semochkin

Reputation: 8897

You need to put print inside loop, like this 

for k in users:
    print (k)

or if you want to more flexibility you can use methods of dict, like keys or values, and you can do like this for more readble output: 

for k in users:
    print (k : x[k])

Upvotes: 0

Marcus Müller
Marcus Müller

Reputation: 36354

Two notes before I come to the point:

First,

[x for x in whatever]

is totally redundant, 

whatever

would yield the same indices.

In your case, it would be equivalent to

print users[range(0,9)]

which is the same as 

print users[range(9)]

which won't work, because users doesn't support indexing with a list.

Second,

you shouldn't use a dictionary if your keys are integers that are consecutive and start at 0. That's a list.

What you can do is just use the different methods of a dictionary, e.g.

print users.items()

or

print users.keys()

or even

print "\n".join("key %s has value %s" % item for item in users.items())

if you want your code to look more like it was written in a functional language. Which Python is not. It has functional aspects. It's not always easiest to read when used in a functional matter. I would just stick with your original code.

Upvotes: 2

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