Reputation: 195
I have a class of items and a function that returns it's size. I have the operator == which gets 2 const parameters of the class type and return the result of item1.size() == item2.size (). size function is non-parametres func and need only hidden this parameter.
The problem is when I try to use size on const reference of classes, it's give me an error:
'function' : cannot convert 'this' pointer from 'type1' to 'type2'
The compiler could not convert the this pointer from type1to type2.
This error can be caused by invoking a non-const member function on a const object. Possible resolutions:
Remove the const from the object declaration.
Add const to the member function.
The piece of code as it is on my problem:
bool operator==(const CardDeck& deck1, const CardDeck& deck2){
if (deck1.size() != deck2.size()) {
return false;
}
//...
}
The error:
'unsigned int CardDeck::size(void)' : cannot convert 'this' pointer from 'const CardDeck' to 'Cardeck&'
If I want that size will get the object as const, I must make it friend and pass the object as const refference or is there a way to tell size get the class type this as constant ??? Thanks for helping.
Upvotes: 1
Views: 729
Reputation: 96291
Most likely you forgot to qualify the size
member function as const: size_t size() const { return /* compute/return size */; }
The alternative is that you really did typo CardDeck
as Cardeck
somewhere (the spelling from your error message).
Upvotes: 3