CODEWITHSUNDEEP
javaswingtimer
OverlclockedPotato
OverlclockedPotato

Reputation: 13

How to stop a swing timer without terminating?

I'm using a swing timer to get the x-position of a moving object every second for 10 seconds and save it in an array. Right now, the only way I can stop the repeat of the timer is using System.exit(0);. How do I stop the timer and continue executing the rest of the code?

int k=0;
{
int delay = 1000; //milliseconds
ActionListener taskPerformer = new ActionListener() 
{

    public void actionPerformed(ActionEvent evt) 
    {
        for (int i=0;i<1;i++)
        {

            obj1pos[k]=x;
            System.out.println(obj1pos[k]);
            k+=1;
        }
        if (k>=10){
            for (int i=0;i<10;i++){
                System.out.print(obj1pos[i]+", ");}
            System.exit(0);}


     }
};

new Timer(delay, taskPerformer).start();


}

Upvotes: 1

Views: 276

Answers (2)

Ben Orgera
Ben Orgera

Reputation: 38

You could make the timer accessible throughout the class by defining a private Timer at the top of your class;

private Timer timer;

Then define the timer as you do before by stating:

timer = new Timer(delay, taskPerformer).start();

And then in your if just call:

timer.stop();

Upvotes: 1

MadProgrammer
MadProgrammer

Reputation: 347332

The ActionEvent will pass you the source that generated the event, which, in this case, is the instance of the Timer

So you can just cast the ActionEvent#getSource to a Timer and call stop on it when you need to...

if (k>=10){
    for (int i=0;i<10;i++){
        System.out.print(obj1pos[i]+", ");
    }
    System.exit(0);
    ((Timer)(evt.getSource())).stop();
}

Upvotes: 1

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