CODEWITHSUNDEEP
xmlactionscript-3xmllint
Daniel
Daniel

Reputation: 35684

find XML node based on element value when multiples may be present

var xmlData:XML = XML(<data>
    <item>
        <type atr="a">AAA</type>
        <type atr="b">BBB</type>
    </item>
    <item>
        <type atr="c">CCC</type>
    </item>
</data>);


trace(xmlData.item.(type=='AAA')); // does not work
trace(xmlData.item.(type=='CCC')); // works
trace(xmlData.item.type.(@atr=='a').parent()); // works
trace(xmlData.item.type.(@atr=='c').parent()); // works

It seems that I cannot get a node based on its value when siblings are present, unless I use attributes.

Is there a way to retrieve item based on the value when there is an unknown amount of elements, without looping manually or using attributes?

Upvotes: 0

Views: 60

Answers (2)

Daniel
Daniel

Reputation: 35684

I found a way, mostly by randomly trying things...

xmlData.item.type.(child(0)=='BBB').parent();

or 

xmlData.item.type.(children()=='BBB').parent();

Upvotes: 1

Aaron Beall
Aaron Beall

Reputation: 52133

You could use XMLList/contains:

trace(xmlData.item.(type.contains(<type atr="a">AAA</type>)))
// or
trace(xmlData.item.(type.contains("AAA")))

Upvotes: 0

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