Reputation: 3207
Below test1.cpp compiles, but test2.cpp does not. The only difference between the two is that I define Handle::add_it
within the class declaration in test1.cpp, but outside in test2.cpp.
test1.cpp: g++ test1.cpp -o test1 -std=c++11
#include <iostream>
template<typename B>
class Handle
{
public:
decltype(B.operator(int)) add_it(int x)
{
return b(x);
}
B b;
};
struct Add1
{
int operator()(int x)
{
return x + 1;
}
};
int main()
{
Handle<Add1> h;
std::cout << h.add_it(5) << std::endl;
}
test2.cpp: g++ test2.cpp -o test2 -std=c++11
#include <iostream>
template<typename B>
class Handle
{
public:
decltype(B.operator(int)) add_it(int x);
B b;
};
template<typename B>
decltype(B.operator(int)) Handle<B>::add_it(int x)
{
return b(x);
}
struct Add1
{
int operator()(int x)
{
return x + 1;
}
};
int main()
{
Handle<Add1> h;
std::cout << h.add_it(5) << std::endl;
}
Errors
test2.cpp:13:11: error: expected primary-expression before ‘.’ token
decltype(B.operator(int))
^
test2.cpp:13:20: error: expected type-specifier before ‘(’ token
decltype(B.operator(int))
^
test2.cpp:13:21: error: expected primary-expression before ‘int’
decltype(B.operator(int))
Upvotes: 6
Views: 2368
Reputation: 42889
You can amend this by using std::declval
:
template<typename B>
class Handle
{
public:
decltype(std::declval<B>()(int())) add_it(int x) {
return b(x);
}
B b;
};
Or outside the definition of the class:
template<typename B>
class Handle {
public:
decltype(std::declval<B>()(int())) add_it(int x);
B b;
};
template<typename B>
decltype(std::declval<B>()(int())) Handle<B>::add_it(int x) {
return b(x);
}
Upvotes: 4