CODEWITHSUNDEEP
bashif-statement
user5781756
user5781756

Reputation:

bash - omitting if statement

I'm sorry for likely trivial question but i start learning Bash two days ago. I'm still newbie :).

if [ ! -d $backup_directory ]; then
        echo $'Backup device is not mounted or is mounted somewhere elese\a!'
        echo "Press enter when sdc device mounted to /mnt/sdc1 or past alternative path:"
        while [ ! -e $backup_directory ]; do
                alter_dev_path="" 
                read $alter_dev_path
                if [ "$alter_dev_path" != "" ]; then
                        $backup_directory=$alter_dev_path
                        $destination_directory=$alter_dev_path+"/sh-backup"
                        $result_path=$destination_directory+"/programming-base"
                fi
        done
fi

Thats is if statement from my backup script. I want program to ask me about device mount directory. But while loop is just omitting if statement inside with no effect. Thanks, Siery.

Upvotes: 1

Views: 77

Answers (1)

that other guy
that other guy

Reputation: 123410

To read a value:

read $alter_dev_path  # Wrong
read alter_dev_path   # Correct

To assign a value:

$destination_directory=$alter_dev_path+"/sh-backup"  # Wrong
destination_directory="$alter_dev_path/sh-backup"    # Correct

Upvotes: 2

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