Reputation: 850
I have the following XML format, and I want to pull out the values for name, region, and status using python's xml.etree.ElementTree module.
However, my attempt to get this information has been unsuccessful so far.
<feed>
<entry>
<id>uuid:asdfadsfasdf123123</id>
<title type="text"></title>
<content type="application/xml">
<NamespaceDescription xmlns="http://schemas.microsoft.com/netservices/2010/10/servicebus/connect" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Name>instancename</Name>
<Region>US</Region>
<Status>Active</Status>
</NamespaceDescription>
</content>
</entry>
<entry>
<id>uuid:asdfadsfasdf234234</id>
<title type="text"></title>
<content type="application/xml">
<NamespaceDescription xmlns="http://schemas.microsoft.com/netservices/2010/10/servicebus/connect" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Name>instancename2</Name>
<Region>US2</Region>
<Status>Active</Status>
</NamespaceDescription>
</content>
</entry>
</feed>
My code attempt:
NAMESPACE = '{http://www.w3.org/2005/Atom}'
root = et.fromstring(XML_STRING)
entry_root = root.findall('{0}entry'.format(NAMESPACE))
for child in entry_root:
content_node = child.find('{0}content'.format(NAMESPACE))
for content in content_node:
for desc in content.iter():
print desc.tag
name = desc.find('{0}Name'.format(NAMESPACE))
print name
desc.tag is giving me the nodes I want to access, but name is returning None. Any ideas what's wrong with my code?
Output of desc.tag:
{http://schemas.microsoft.com/netservices/2010/10/servicebus/connect}Name
{http://schemas.microsoft.com/netservices/2010/10/servicebus/connect}Region
{http://schemas.microsoft.com/netservices/2010/10/servicebus/connect}Status
Upvotes: 3
Views: 12077
Reputation: 850
I don't know why I didn't see this before. But, I was able to get the values.
root = et.fromstring(XML_STRING)
entry_root = root.findall('{0}entry'.format(NAMESPACE))
for child in entry_root:
content_node = child.find('{0}content'.format(NAMESPACE))
for descr in content_node:
name_node = descr.find('{0}Name'.format(NAMESPACE))
print name_node.text
Upvotes: 2
Reputation: 11961
You can use lxml.etree
along with default namespace mapping to parse the XML as follows:
content = '''
<feed>
<entry>
<id>uuid:asdfadsfasdf123123</id>
<title type="text"></title>
<content type="application/xml">
<NamespaceDescription xmlns="http://schemas.microsoft.com/netservices/2010/10/servicebus/connect" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Name>instancename</Name>
<Region>US</Region>
<Status>Active</Status>
</NamespaceDescription>
</content>
</entry>
<entry>
<id>uuid:asdfadsfasdf234234</id>
<title type="text"></title>
<content type="application/xml">
<NamespaceDescription xmlns="http://schemas.microsoft.com/netservices/2010/10/servicebus/connect" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Name>instancename2</Name>
<Region>US2</Region>
<Status>Active</Status>
</NamespaceDescription>
</content>
</entry>
</feed>'''
from lxml import etree
tree = etree.XML(content)
ns = {'default': 'http://schemas.microsoft.com/netservices/2010/10/servicebus/connect'}
names = tree.xpath('//default:Name/text()', namespaces=ns)
regions = tree.xpath('//default:Region/text()', namespaces=ns)
statuses = tree.xpath('//default:Status/text()', namespaces=ns)
print(names)
print(regions)
print(statuses)
Output
['instancename', 'instancename2']
['US', 'US2']
['Active', 'Active']
This XPath/namespace functionality can be adapted to output the data in any format you require.
Upvotes: 1