Reputation: 2463
I have a public property which is an object that contains numerous properties itself. Using ASP.net MVC, when I serialize the JSON data I simply add the [JsonIgnore]
attribute wherever I use the object so it doesn't display the contents.
Is there a way to add the [JsonIgnore]
attribute to the class so it never is serialized?
//[JsonIgnore] ??
public class DataObj
{
public string ConnectionName { get; set; }
public string Query { get; set; }
...
}
public class Customer
{
public string First { get; set; }
public string Last { get; set; }
[JsonIgnore]
public DataObj Foo { get; set; }
}
public class ShipAddress
{
public string Street { get; set; }
public string City { get; set; }
public string Country { get; set; }
[JsonIgnore]
public DataObj Foo { get; set; }
}
My solution after receiving the code provided by jvanrhyn.
Also, here is a link that explains more.
public class DataObjFilterContractResolver : DefaultContractResolver
{
public static readonly DataObjFilterContractResolver Instance = new DataObjFilterContractResolver();
protected override JsonProperty CreateProperty(MemberInfo member,MemberSerialization memberSerialization)
{
var property = base.CreateProperty(member, memberSerialization);
if (property.DeclaringType.Name.StartsWith("DataObj") || property.PropertyName == "DataObj")
{
property.ShouldSerialize = instance => false;
}
return property;
}
}
public class UtcJsonResult : JsonResult
{
public UtcJsonResult(object data)
{
Data = data;
JsonRequestBehavior = JsonRequestBehavior.AllowGet;
}
private const string DateFormat = @"yyyy-MM-dd HH:mm:ssZ";
public override void ExecuteResult(ControllerContext context)
{
if (context == null) throw new ArgumentNullException("context");
if (Data == null) return;
var response = context.HttpContext.Response;
response.ContentType = !string.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
if (ContentEncoding != null) response.ContentEncoding = ContentEncoding;
var isoConvert = new IsoDateTimeConverter {DateTimeFormat = DateFormat};
JsonConvert.DefaultSettings =
() => new JsonSerializerSettings
{ ContractResolver = new DataObjFilterContractResolver()}; //<--- Used here
var json = JsonConvert.SerializeObject(Data, isoConvert);
response.Write(json);
}
}
Upvotes: 2
Views: 2108
Reputation: 2824
You can add a Contract Resolver in your project.
public class ShouldSerializeContractResolver : DefaultContractResolver
{
public new static readonly ShouldSerializeContractResolver Instance =
new ShouldSerializeContractResolver();
protected override JsonProperty CreateProperty(MemberInfo member,
MemberSerialization memberSerialization)
{
JsonProperty property = base.CreateProperty(member, memberSerialization);
if (property.DeclaringType == typeof(DataObj))
{
property.ShouldSerialize =
instance =>
{
return false;
};
}
return property;
}
}
Upvotes: 3