CODEWITHSUNDEEP
pythonnumberscomparisontypeerror
Beginner
Beginner

Reputation: 1

Why is this comparison failing?

print("Enter the number you want to test")
Num1 = input("Enter your number here:")
if (Num1%1 == '0' and Num1%Num1 == '0'):
    print ("This number is prime number")
else:
    print("This number is nor prime number")

This is failing with an error of TypeError: not all arguments converted during string formatting. What is the cause and how can I fix it?

Upvotes: 0

Views: 74

Answers (1)

ᴀʀᴍᴀɴ
ᴀʀᴍᴀɴ

Reputation: 4528

input returns a string , you should convert it to int:

Num1 = int(input("Enter your name here:"))

And if parts changed to : 

if (Num1%1 == 0 and Num1%Num1 == 0):

However your code logic for realize that a number is prime or not is not correct , you should check that number has a factor or not , you should write a for loop through it's lower numbers and realize that.it's simple but I think it's better for you that write it yourself.

Upvotes: 1

Related Questions