CODEWITHSUNDEEP
pythonregexpython-3.x
rock321987
rock321987

Reputation: 11042

Regular expression for finding more than 4 consecutive repeating characters in a string

I want to find out more than 4 consecutive repeating characters within a string. e.g. (string is lowercased)

bbaaaaa ---> yes (5 consecutive a's)
bbaa   ---> no
aabbbbbccdddddee ---> yes (5 consecutive b's)

One possible solution is to loop over a to z and use character{4,} where character can be anyone from a to z.

Is there any one liner for it?

I apologize if its duplicate

Upvotes: 2

Views: 2989

Answers (1)

vks
vks

Reputation: 67988

import re
[i for i,j in re.findall(r"((.)\2{3,})",test_str)]

This should do it for you.

Output:

['aaaaa', 'bbbbb', 'ddddd']

Upvotes: 4

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