CODEWITHSUNDEEP
c#silverlightargb
Hosain
Hosain

Reputation: 101

What does the >> operator do in C#?

I'm quite new to C# and trying to do a basic image processing software. I understand this snippet extracts A,R,G,B from an ARGB int value of a WriteableBitmap pixel "current"

for(int i = 0; i < bitmapArray.Length; i++) {
    var current = bitmapArray[i];

    var alpha = (byte)(current >> 24);
    var red = (byte)(current >> 16);
    var green = (byte)(current >> 8);
    var blue = (byte)(current);
    //Some code
 }

What is ">>" doing to convert the values?

Also, If I do some calculations to the r,g and b individually, how do I convert them back to an integer ARGB value to replace the original pixel with the new one?

Thanks in advance.

Edit: thanks guys, it makes sense now.

Upvotes: 10

Views: 539

Answers (3)

Ed Swangren
Ed Swangren

Reputation: 124722

It is the binary shift operator.

If you have a color defined by (a, r, g, b), it's binary representation would look like this (assuming a channel depth of 8 bits):

AAAAAAAA RRRRRRRR GGGGGGGG BBBBBBBB

So, shift that whole thing over 24 places and you are left with the alpha channel

AAAAAAAA

Shift by 16 and you get the alpha channel and the red channel

AAAAAAAARRRRRRRR

Now, since that is cast as a byte, only the first 8 bits are extracted

(byte)AAAAAAAARRRRRRRR == RRRRRRRR

You could also get the red channel by shifting 16 places and AND'ing with 11111111 (0xFF)

AAAAAAAARRRRRRRR &
0000000011111111
----------------
00000000RRRRRRRR

Upvotes: 16

Robert Harvey
Robert Harvey

Reputation: 180858

It is shifting the bits of the current value to the right. In the case of this particular code snippit, it appears to be extracting each byte of color information from the selected bitmap array element into individual color bytes.

http://msdn.microsoft.com/en-us/library/xt18et0d.aspx

Assuming that your array contains ints, to get a computed value back into the array element, you would reverse the bit-shifting process and OR the results back together, like so:

int current = (alpha << 24) | (red << 16) | (green << 8) | blue;

Upvotes: 12

LukeH
LukeH

Reputation: 269498

Further to Robert's answer -- and to cover the second part of your question -- you can combine the separate components back to an integer using the << (left-shift) and | (bitwise OR) operators:

int combined = (alpha << 24) | (red << 16) | (green << 8) | blue;

Upvotes: 2

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