CODEWITHSUNDEEP
phplaravel-4
nicolassiuol
nicolassiuol

Reputation: 83

Laravel 4.2 is_online article

I'm confronted to a little problem, i try to add a method to show only online article, but i want to know how do implement this method. In my DB i have a row is_online (Int) for 0=> offline, 1=>online, how do implement that for my view.

in my models with 

public function isonline(){}

or in my PostController in my request of post find.

And after need to add in my admin panel a check box in Post create to change the status off article (online or offline-draft).

Upvotes: 0

Views: 62

Answers (2)

Ravi Hirani
Ravi Hirani

Reputation: 6539

You just need to find all records who have flag is_online = 1.

You can write one method in your PostController like

Public function getOnlineRecords{

    $records = YourModel::where('is_online','=',1)->get();
    return View::make('your_view_path',['records'=>$records]);
}

In your View file, you need to write:-

 {{ Form::checkbox('your_field_name', 'value', true) }}

If you want to default the value as checked, pass true as the third argument.

Upvotes: 0

Ehs4n
Ehs4n

Reputation: 802

You should use Eloquent scope in your code by creating online scope in your model.

public function scopeOnline($query)
{
    return $query->where('is_online', 1);
}

Draft posts

public function scopeDrafts($query)
{
    return $query->where('is_online', 0);
}

Then in your code you can simply use it like this.

$onlinePosts = Post::online()->get();

$draftPosts = Post::drafts()->get();

Upvotes: 3

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