CODEWITHSUNDEEP
windowsbatch-file
user4312749
user4312749

Reputation:

Batch - echo is off issue

I've checked other tons of answers related to my issue and none worked. I suppose it's a syntax typo, but I cannot seem to find it.

My script should simply tell me if a process is running, then save the path into a variable, go to that path and delete the .exe.

Unfortunately, I get ECHO is OFF. Any ideas why?

@echo off
setlocal EnableDelayedExpansion

set /p PROGRAM=NAme of the exe:

tasklist /FI "IMAGENAME eq %PROGRAM%" 2>NUL | find /I /N "%PROGRAM%">NUL
if "%ERRORLEVEL%"=="0" echo. %PROGRAM% is running

for %%i in (%PROGRAM%) do (
    echo %%~$PATH:i
    set PROGRAM_PATH=%%~$PATH:i
)

cd %PROGRAM_PATH%

del /F %PROGRAM_PATH%

pause

Upvotes: 2

Views: 108

Answers (1)

user4312749
user4312749

Reputation:

So, I realized that my program wasn't doing what I wanted because the .exe didn't exist.

So, I modified a little bit the script, so that I will handle that case:

  • if the .exe is running, exit because I won't be able to delete a already in use .exe anyway;
  • otherwise go to its location and delete it.

My final program:

@echo off
setlocal EnableDelayedExpansion
goto start_program

:start_program
    set /p PROGRAM=Name of exe(ex:cmd.exe):
    tasklist /FI "IMAGENAME eq %PROGRAM%" 2>NUL | find /I /N "%PROGRAM%">NUL

    if "%ERRORLEVEL%"=="0" do (
        goto enter_program
    )
    if "%ERRORLEVEL%"=="1" do (
        goto exit_program
    )

:enter_program
    for %%i in (%PROGRAM%) do (
        set PROGRAM_PATH=%%~$PATH:i
    )
    cd %PROGRAM_PATH%
    del /f %PROGRAM_PATH%
    goto:eof

:exit_program
    goto:eof

Thanks for tips Ryan and jeb

Upvotes: 2

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