Reputation: 5770
I am creating a "change password" form where the user is required to enter the previous password first, then a new password (twice).
I should compare the entered "previous password" to the one already stored.
My web application uses an LDAP server to store user credentials. Password is apparently stored using SHA.
So what I do is get the previous password entered by the user, digest it using SHA1, then compare it.
String oldPass = request.getParameter("oldpass");
String enteredOldPass= App.getInstance().getCipher().cipher(oldPass);
String ldapPassword= ctx.get("userpassword");
But this isn't working, because the passwords are different. When I store "test" in the LDAP I obtain {sha}qUqP5cyxm6YcTAhz05Hph5gvu9M=
when calling .get("userPassword")
, whilst I get a94a8fe5ccb19ba61c4c0873d391e987982fbbd3
when hashing "test" by myself.
What am I doing wrong here? It seems that a step is missing since my result is purely hex, while the one I get from the LDAP is ASCII. But I tried converting the string to hex (using string to hex online converters) but the result is still differnet.
Upvotes: 1
Views: 1522
Reputation: 1
you must convert to binary, then convert to base64. Try this:
echo -n "test" | sha1sum | awk '{print $1}' <br>
The result will be a94a8fe5ccb19ba61c4c0873d391e987982fbbd3
echo -n "test" | sha1sum | awk '{print $1}' | xxd -r -p | base64
The result will be qUqP5cyxm6YcTAhz05Hph5gvu9M=
Upvotes: -1
Reputation: 310980
You don't do any of this.
Upvotes: 2