Reputation: 505
I would like to write a Python script that takes some necessary positional and some optional command-line arguments via argparse
:
a
,b
,c
, and the optional arguments x
,y
,z
.a
,b
,c
to be passed as *args
, and x
,y
,z
to be passed as **kwargs
, the latter retaining their names.Here is some example code:
import argparse
def parse():
parser = argparse.ArgumentParser()
parser.add_argument('a', help='1st arg')
parser.add_argument('b', help='2nd arg')
parser.add_argument('c', help='3rd arg')
parser.add_argument('-x', '--x', help='1st kwarg')
parser.add_argument('-y', '--y', help='2nd kwarg')
parser.add_argument('-z', '--z', help='3rd kwarg')
return parser.parse_args()
def func(*args, **kwargs):
a, b, c = args
print 'a=', a
print 'b=', b
print 'c=', c
for k, v in kwargs.iteritems():
print '%s=' % k, v
if __name__ == '__main__':
all_args = parse()
### need to split all_args into args and kwargs here ###
func(*args, **kwargs)
Upvotes: 3
Views: 2747
Reputation: 231605
The Namespace
you get back from parse_args
will have attributes corresponding to each of your arguments. There will be no distinction between the positional arguments and the optionals, e.g.:
args
Namespace(a='1',b='one',x='foo', y=...)
Which, as is well documented, can be accessed as:
args.a
args.x
etc.
The Namespace
can also be turned into a dictionary:
vars(args)
{'a'='1', 'b'='one', etc.}
You can pass the dictionary to a function as **kwargs
. That's standard Python argument practice.
If you want to pass some arguments as *args
you'll have to split those off the Namespace
or dictionary yourself. Nothing in argparse
will do that for you.
You could write a function like (not tested):
def split_args(args):
vargs = vars(args)
alist = ['a','b','c']
args1 = []
for a in alist:
v = vargs.pop(a)
args1.append(v)
return args1, vars
Or more compactly, put the pop
in a list comprehension:
In [702]: vargs = dict(a=1,b=3,c=4,x=5,y=3,z=3)
In [703]: [vargs.pop(a) for a in ['a','b','c']]
Out[703]: [1, 3, 4]
In [704]: vargs
Out[704]: {'y': 3, 'x': 5, 'z': 3}
In [705]: def foo(*args,**kwargs):
.....: print(args)
.....: print(kwargs)
.....:
In [706]: vargs = dict(a=1,b=3,c=4,x=5,y=3,z=3)
In [707]: foo(*[vargs.pop(a) for a in ['a','b','c']],**vargs)
(1, 3, 4)
{'x': 5, 'z': 3, 'y': 3}
The parser
determines whether an argument is an optional
vs. positional
by its option_strings
attribute. add_argument
returns an Action
subclass, which will have attributes like:
MyAction(option_strings=[], dest='baz', nargs=None, const=None, default=None, type=None, choices=None, help=None, metavar=None)
This is a positional
because option_strings
is an empty list.
MyAction(option_strings=['-m', '--mew'], dest='mew', nargs=None,...)
is an optional
because that list is not empty.
The parser matches input strings with the option_strings
and nargs
, and then passes values to the __call__
method of the matching Action
. This method is defined like:
def __call__(self, parser, namespace, values, option_string=None):
setattr(namespace, self.dest, values)
This is the default store
action. The values are put in the Namespace
as the dest
attribute.
The option_string
parameter is the string that triggered this call, something like '-m' or '--mew', or None
for a positional
. The defined action types don't make use of this, but a user-defined Action class could do something.
class MyAction(argparse._StoreAction):
def __call__(self, parser, namespace, values, option_string=None):
# store option_string along with values in the Namespace
setattr(namespace, self.dest, [values,option_string])
Or you could do something special with positionals
, e.g.
if option_string is None:
# append values to a `star_args` attribute
# rather than self.dest
With an action like this positionals
could be accessed after parsing as:
args.star_args
The parser does maintain a list attribute like this. The extras
that parse_known_args
returns are stored temporarily in the Namespace
in the '_UNRECOGNIZED_ARGS_ATTR' attribute.
Upvotes: 3